Math, asked by Zuwa, 2 months ago

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Answered by AkashMathematics
2

hey, mate

here AKASHITEMHEAVEN

HERE IS YOUR ANSWER IN THE ATTACHMENT

THANKS FOR ASKING

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Answered by Anonymous
2

Answer  \\ we \: know \: that \:  \\ (x + y + z) {}^{2}  = x {}^{2}  + y { }^{2}  + z {}^{2}  + 2xy + 2yz + 2xz \\  \\ 4x {}^{2}  + 9y {}^{2}  + 16z {  }^{2}  +  12xy - 24yz - 16xz \\  = (2x) {}^{2}  + (3y) {}^{2}  + ( - 4z) {}^{2} + 2 \times 2x \times 3y + 2 \times 3y \times ( - 4z) + 2 \times 2x \times ( - 4z) \\  = (2x + 3y - 4z) {}^{2}

Hope it helps.

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