Refraction cannot cause bending as light moves one surface to another if the incident and refraction angles I and r are related as:
(a) i= r = 900 (b) i= r = 0 (c) i – 900 , r = 00 (d) i ? r = 0
I had it on my test for class XII.
Answers
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when i = r = 0 , the incident light rays are perpendicular to the surface of the interface between the two media. Light rays enter from medium1 to medium2.
Mu2 sin r = Mu1 sin i => r = 0 if and when i = 0.
When i = 90 deg, the light ray is moving along the surface of the boundary between the media. It does not enter 2nd medium. There is no question of bending.
if i=90, then r cannot be 0.
Mu2 sin r = Mu1 sin i => r = 0 if and when i = 0.
When i = 90 deg, the light ray is moving along the surface of the boundary between the media. It does not enter 2nd medium. There is no question of bending.
if i=90, then r cannot be 0.
Answered by
1
Answer:
option b I=r=0 because incident ray fall perpendicular with respect to refraction surface
#and angle i is taken with respect to normal which is zero degree.
#light follows it's paths thus angle r is zero degree
Explanation:
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