Question

refraction through a glass slab ​

Answer 1

Answer:

When light rays travelling through air enters glass slab, they get refracted and bend towards the normal. Now the direction of refracted ray changes again when it comes out of the glass slab into air. Since the ray of light I know travelling from denser medium to rarer medium, it bends away from the normal.

Explanation:

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Answer 2

Let , us see the refraction through a glass slab

$\setlength{\unitlength}{1cm}\begin{picture}(12,12)\put(0,0){\framebox(9,5)}\multiput(4,6.5)(2,-5){2}{\line(0,-1){3}}\thicklines\qbezier(4,5)(4,5)(6,0)\qbezier(1.5,7.5)(3,6)(4,5)\qbezier(6,0)(6,0)(8.5,-2.5)\multiput(4,5)(0.5,-0.5){14}{\line(1,-1){0.4}}\linethickness{0.24mm}\qbezier(3.5,5.5)(3.7,5.9)(4,5.7)\qbezier(6,-0.6)(6.3,-0.85)(6.5,-0.5)\qbezier(4,4)(4.3,3.8)(4.38,4.1)\qbezier(6,1)(5.8,1.2)(5.62,0.9)\put(2.5,6.5){\line(-1,0){0.4}}\put(2.5,6.5){\line(0,1){0.4}}\put(7.5,-1.5){\line(-1,0){0.4}}\put(7.5,-1.5){\line(0,1){0.4}}\qbezier(5,2.5)(5,2.5)(4.6,2.7)\qbezier(5,2.5)(5,2.5)(5.2,2.9)\thinlines\qbezier(8,-2)(8,-2)(9.5,-0.5)\put(3.8,6.7){\bf M}\put(3.8,3){\bf M'}\put(5.8,1.8){\bf N}\put(5.8,-2){\bf N'}\put(1,7.7){\bf A}\put(4.3,5.3){\bf B}\put(5.4,-0.5){\bf C}\put(7.5,-2.4){\bf D}\put(9.8,-0.5){\rm E}\put(0.5,5.5){\sf AIR}\put(0.5,2.5){\sf GLASS}\put(0.5,-0.8){\sf AIR}\put(3.5,6){\bf i}\put(6.4,-1.2){\bf e}\linethickness{0.24mm}\qbezier(4,3.85)(4.3,3.7)(4.4,3.9)\qbezier(6,1.15)(5.8,1.3)(5.6,1.1)\put(5,5.5){\sf DE=Lateral Displacement}\end{picture}$

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