replace * in the number 64*719 by the smallest , so that it is divisible by 11
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Answer: 2
Step-by-step explanation:
if a number is divisible by 11, then the difference between the sum of alternate digit is either 0 or a multiple of 11
Let x be missing number.
(4 + 7 +9) - (6 + x + 1) = 20-7-x = 13-x
if 13-x =0, then x = 13, which is not possible as x is a single digit
so 13 - x = 11, then x =2
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