Question

the parallel sides of trapezium are 25cm,13cm and non parallel side of trapezium are equal each measuring 10cm find the area of trapezium

Answer 1

Hey Mate

$\huge\mathfrak\pink{anSwer}$

$\huge\bold{Solution}$
$area \: of \: trapezium = \frac{1}{2} \times h1 \times (sum \: of \: parallel \: side) \\ \frac{1}{2} \times 10 \times (25 + 13 {cm}^{2} ) \\ \frac{1}{2} \times10 \times 38 {cm}^{2} \\ \frac{380}{2} = 190 {cm}^{2}$
Hope it helps uh

Answer 2

Applying Pythagoras theorem

Hy^2 = base^2+perpendicular^2

(10)^2= (6)^2+perp^2

100= 36 +perp^2

Perp^2= 100-36 = 64

Perp=

$\sqrt{64} = 8cm$

Area of trapezium =1/2 (sum of parallel sides) *height

=1/2 (13+25)*8

=1/2*38*8

=152cm^2

Your answer is 152cm^2

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