Represent root 8.3 on the number line
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See the diagram.
Draw AD a horizontal line. The n draw AB' perpendicular to AD at A using tool or standard procedure. Draw an arc of radius 1.4 units to cut AB'. So AB = 1.4. Now draw an arc from B to cut AD at C, with a radius = 3.2 units.. So BC = 3.2. Now AC = √8.28.
Now, Draw CE perpendicular to AD at C. Draw CF as bisector of angle at C. Draw an arc of radius 0.2 units to cut CF at G. Now draw a horizontal line from G parallel to AD and perpendicular to CE. It cuts CE at H.
Now CH will be √0.02. Now join AH. It will be √8.30.
Draw an Arc with A as center, and AH as radius to cut AD at I. Then AI will be equal to √8.30 on the real number line.
Draw AD a horizontal line. The n draw AB' perpendicular to AD at A using tool or standard procedure. Draw an arc of radius 1.4 units to cut AB'. So AB = 1.4. Now draw an arc from B to cut AD at C, with a radius = 3.2 units.. So BC = 3.2. Now AC = √8.28.
Now, Draw CE perpendicular to AD at C. Draw CF as bisector of angle at C. Draw an arc of radius 0.2 units to cut CF at G. Now draw a horizontal line from G parallel to AD and perpendicular to CE. It cuts CE at H.
Now CH will be √0.02. Now join AH. It will be √8.30.
Draw an Arc with A as center, and AH as radius to cut AD at I. Then AI will be equal to √8.30 on the real number line.
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kvnmurty:
clik on thanks... select best ans..
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