resistance of a metal wire of length one metre is 25 ohms if the radius of the wire is 0.15 mm calculate the resistivity of the material
devanayan2005:
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Answered by
15
Step-by-step explanation:
recall resistivity ρ = π r2 R / L
Data :
r = 0.15 mm = 1.5 * 10-4 m
R = 25 ohm
L = 1 m
Plug this for ρ and you get
ρ = 3.14 * (1.5 * 10-4)2 * 25 / 1 = 176.625 * 10-8 = 1.77 * 10-6 ohm m
Answered by
9
Hello friend
Resistance , R = 26Ω
Length of wire , L = 1m
diameter of circular part of wire ,d = 0.3mm = 0.3 × 10⁻³m
so, base area of wire , A = πr² = πd²/4 [ ∵d = 2r]
= 3.14 × (0.3 × 10⁻³)²/4m²
= 3.14 × 9 × 10⁻⁸/4 m²
= 28.26/4 × 10⁻⁸ m² = 7.06 × 10⁻⁸ m²
Now, use formula,
R = ρL/A
Here, R is the resistance, ρ is the resistivity , L is the length of wire and A is the base area of it .
So , ρ = RA/L = 26Ω × 7.06 × 10⁻⁸m²/1m
ρ = 1.8356 × 10⁻⁶ Ωm
Hence, resistivity is 1.8356 × 10⁻⁶ Ωm at 20°C
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