resolve 1÷(x-5)(x+7) into partial fraction
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1/(x-5)(x+7)= A/x-5 + B/x+7
= A(x+7)+B(x-5)/(x-5)(x+7)
=>1=A(x+7)+B(x-5)
comparing the coefficients of x²,x and constants, we'll get the values of A and B..
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= A(x+7)+B(x-5)/(x-5)(x+7)
=>1=A(x+7)+B(x-5)
comparing the coefficients of x²,x and constants, we'll get the values of A and B..
HOPE IT HELPS YOU..
MARK IT AS A BRAINLIEST ANSWER..
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