Question

resolve into factors
2a^2 x-2a^2 y – 3b^2 x +3b^2 y

Answer 1

Answer:

$2a^{2}x-2a^{2}y-3b^{2}x+3b^{2}y\\ =2a^{2}(x-y)-3b^{2}(x-y)\\ =(x-y)(2a^{2}-3b^{2})\\ =(x-y)[(\sqrt{2}a)^{2}-(\sqrt{3}b)^{2})\\ =(x-y)(\sqrt{2}a+\sqrt{3}b)(\sqrt{2}a-\sqrt{3}b)$

Answer 2

Answer:

7/2 as usual number depends