Rhombus show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects Angle B as well as angle d
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[In rhombus all side are equal and diagonols
⇒AB=BC=CD=DA
⇒AC⊥BD
In ΔABC
⇒AB=BC
⇒∴∠CAB=∠ACB
⇒AO=OC
∴∠ABO=∠CBO
and simillarly in ΔADC
⇒AD=DC
⇒AO=OC
∴corresponding angle are equal
⇒∠DAC=∠DCA
and∠CDO=∠ADO
Hence, ACbisect ∠A and ∠C and BDbisects ∠Band∠D
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