RIDDLE!
There are four prisoners. All four prisoners will be freed, if at least one of them correctly guesses the color of the hat on his head.
They can't speak to each other, and they can't touch each other.
Number 1 sees number 2 and 3's hats.
Number 2 sees number 3's hat.
Number 3 sees only the wall.
Number 4 sees only the wall.
There are no mirrors.
They all know that there are 2 black hats and 2 white hats, and that there are four people.
They know their placement in this room is as shown in the pic attached.
Can the four prisoners be freed? If so, how?
[Better if don't verify internet, Think Yourself and answer :)]
Attachments:
remavijayan0p13wvl:
they can be freed as number 2 can see number three's hat
they have to guess there own hat
their*
oh
good question for testing our logic
Thanks! And @questionEverything, that can't be done :P
where did u get it from
Well, It was asked by our teacher -_- He knows the answer but not telling, let it be. We will find it ;)
oh ok
Answers
Answered by
9
Smart Answer;
They can remove the caps from their heads and see the colour, Simple!
Detailed answer;
Got it!
See, if 2 and 3 were wearing same coloured hats, then, 1 would come to know the colour of his Hat and declare his colour.
But since, 1 didn't declare any answer, so 2 will come to know that his hat's colour is not same as 3.
Since 2 can see 3 is wearing White hat, So, he can be sure, that he is wearing Black hat.
Read these statements 3-4 times amd you will understand it!
☺
~ QuestionEverything.
They can remove the caps from their heads and see the colour, Simple!
Detailed answer;
Got it!
See, if 2 and 3 were wearing same coloured hats, then, 1 would come to know the colour of his Hat and declare his colour.
But since, 1 didn't declare any answer, so 2 will come to know that his hat's colour is not same as 3.
Since 2 can see 3 is wearing White hat, So, he can be sure, that he is wearing Black hat.
Read these statements 3-4 times amd you will understand it!
☺
~ QuestionEverything.
But according to the pic, answer is right?
I will confirm :)
Answered by
16
your answer is....
prisoner (2) is right person for freedome
if prosoner(2)'s hat is not oposite prisoner(3). then prisoner(1) gave the right answer.
bcoz if prisoner (2)'s and prisoner(3)'s hat is same coulor then prisoner(1)'s hat will oposite coulor...
bcoz hats count is 2white and 2black.
so prison(2)'s hat and prisoner(3)'s hat will not same coulor.
then prisonern(2) never know the hat coulor then so he will slient.
then prisoner(2) will just know that his hat is oposite coulor of prisoner(3)'s hat.
then prison(2) gave always right answered
i hope it is helpfull...
and pls taped brainliest answered.
prisoner (2) is right person for freedome
if prosoner(2)'s hat is not oposite prisoner(3). then prisoner(1) gave the right answer.
bcoz if prisoner (2)'s and prisoner(3)'s hat is same coulor then prisoner(1)'s hat will oposite coulor...
bcoz hats count is 2white and 2black.
so prison(2)'s hat and prisoner(3)'s hat will not same coulor.
then prisonern(2) never know the hat coulor then so he will slient.
then prisoner(2) will just know that his hat is oposite coulor of prisoner(3)'s hat.
then prison(2) gave always right answered
i hope it is helpfull...
and pls taped brainliest answered.
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