Question

Right angled
triangles
BAC & ADC are
right angled at A & D & they are on
same side
of BC . if AC and BD
intersect at P, then
prove
that
APX PC=
PBXDP.​

Answer 1

Answer:

Step-by-step explanation:

Don't no

Answer 2

Answer:

In △APB and △DPC, we have

∠A=∠D=90

∘

and

∠APB=∠DPC [Vertically opposite angles]

Thus, by AA-criterion of similarity, we have

△APB∼△DPC

⇒

DP

AP

=

PC

PB

⇒ AP×PC=DP×PB [Hence proved]