Question

Rohan and mohan together can do a piece of work in 17 days. They both started working and after 7 days. Rohan left the work and then mohan completed rest of the work in 15 more days. If for the job they got a total of rs 5100, then what's the mohan's share.​

Answer 1

Answer:

The work done by Mohan alone is in 20 days .

Step-by-step explanation:

Given as :

Mohan and Rohan can do a piece of work in 12 days

Rohan alone can finish in 30 days

Let The work done by Mohan alone in = x days

According to question

One day work of Mohan and Rohan together = \dfrac{1}{12}

12

1

One day work of Rohan alone = \dfrac{1}{30}

30

1

So, One day work of Mohan alone = \dfrac{1}{x}

x

1

Now,

Mohan and Rohan together 1 day work = Rohan's 1 day work + Mohan's 1 day work

i.e \dfrac{1}{12}

12

1

= \dfrac{1}{30}

30

1

+ \dfrac{1}{x}

x

1

or, \dfrac{1}{x}

x

1

= \dfrac{1}{12}

12

1

- \dfrac{1}{30}

30

1

or, \dfrac{1}{x}

x

1

= \dfrac{5-2}{60}

60

5−2

Or, \dfrac{1}{x}

x

1

= \dfrac{3}{60}

60

3

∴ \dfrac{1}{x}

x

1

= \dfrac{1}{20}

20

1

i.e x = 20

So, The work done by Mohan alone in = x = 20 days

Hence, The work done by Mohan alone is in 20 days . Answer

Step-by-step explanation:

hope its gonna help you

Answer 2

Time and Work

Given:

Mohan and Rohan can do a piece of work in 17 days

7 days they work together and after that Mohan completed the work in 15 more days.

Total money they got ₹ 5100.

To Find:

Share of Mohan in ₹5100.

Explanation:

Let the work done by Rohan  in 1 day  $=\frac{1}{x}$

Let the work done by Mohan in 1 day $=\frac{1}{y}$  

According to question

One day work of Mohan and Rohan together  $=\frac{1}{x}+ \frac{1}{y}$

$\frac{1}{x} +\frac{1}{y} =\frac{1}{17}\\\\\& \\\\7(\frac{1}{x} +\frac{1}{y})+15(\frac{1}{y})=1$

$7(\frac{1}{17})+\frac{15}{y}=1\\\\\frac{15}{y}=\frac{10}{17}\\\\y=\frac{51}{2} =25.5\ days$

$x=51\ days$

So, we can see that efficiency of  Mohan is twice that of Rohan.

Hence , Rohan gets ₹1700 and Mohan gets ₹3400.