Math, asked by pratyushssb, 1 year ago

Rohit tells his son, "Five Years Ago, I was six times as old as you were then. Also, five years from now, I will be five years less than, three times as old as you will be." Represent both the situations algebraically.

Answers

Answered by misa3
13
let ,son's age five years ago be x years
then five years ago,fathers age = 6x years



five years from now (present)
_______________________
son's age will be (x+10)years
A/Q. fathers age will be { 3 (x+10) - 5} years

this is the argebric representation of both the situations.....


hope it helps....

misa3: is my answer correct?
pratyushssb: i dont know
pratyushssb: thats why i asked..
pratyushssb: thanks
misa3: from where this question has come?
pratyushssb: My tution question paper
misa3: ok
Answered by Mohanchandrabhatt
43
Let his son's age age at present be x
Situation 1 - Five years ago,
Our age = x - 5
Rohan's age = 6 ( x - 5 )
Rohan's age = 6x - 30
Situation 2 - Five years later
His son's age = x + 5
Rohan's age = 3 ( x + 5 ) - 5
Rohans's age = 3x + 15 -5
Rohan's age = 3x + 10
SO
6x - 30 + 10 = 3x + 10
6x - 30 + 10 - 10 = 3x
6x - 40 + 10 = 3x
6x -30 = 3x
6x - 3x = 30
3x = 30
x = 30 / 3
x = 10
Thus his son's age now is x = 10
Rohan's age now = 6x - 30 +5
= ( 6 * 10 ) - 30 +5
= 60 - 30 + 5
= 30 + 5
= 35

pratyushssb: well you didnt need to find x and y but thanks
Mohanchandrabhatt: It's time to chose a brillianist answer
Mohanchandrabhatt: Hope my answer will help
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