Rohit tells his son, "Five Years Ago, I was six times as old as you were then. Also, five years from now, I will be five years less than, three times as old as you will be." Represent both the situations algebraically.
Answers
Answered by
13
let ,son's age five years ago be x years
then five years ago,fathers age = 6x years
five years from now (present)
_______________________
son's age will be (x+10)years
A/Q. fathers age will be { 3 (x+10) - 5} years
this is the argebric representation of both the situations.....
hope it helps....
then five years ago,fathers age = 6x years
five years from now (present)
_______________________
son's age will be (x+10)years
A/Q. fathers age will be { 3 (x+10) - 5} years
this is the argebric representation of both the situations.....
hope it helps....
misa3:
is my answer correct?
Answered by
43
Let his son's age age at present be x
Situation 1 - Five years ago,
Our age = x - 5
Rohan's age = 6 ( x - 5 )
Rohan's age = 6x - 30
Situation 2 - Five years later
His son's age = x + 5
Rohan's age = 3 ( x + 5 ) - 5
Rohans's age = 3x + 15 -5
Rohan's age = 3x + 10
SO
6x - 30 + 10 = 3x + 10
6x - 30 + 10 - 10 = 3x
6x - 40 + 10 = 3x
6x -30 = 3x
6x - 3x = 30
3x = 30
x = 30 / 3
x = 10
Thus his son's age now is x = 10
Rohan's age now = 6x - 30 +5
= ( 6 * 10 ) - 30 +5
= 60 - 30 + 5
= 30 + 5
= 35
Situation 1 - Five years ago,
Our age = x - 5
Rohan's age = 6 ( x - 5 )
Rohan's age = 6x - 30
Situation 2 - Five years later
His son's age = x + 5
Rohan's age = 3 ( x + 5 ) - 5
Rohans's age = 3x + 15 -5
Rohan's age = 3x + 10
SO
6x - 30 + 10 = 3x + 10
6x - 30 + 10 - 10 = 3x
6x - 40 + 10 = 3x
6x -30 = 3x
6x - 3x = 30
3x = 30
x = 30 / 3
x = 10
Thus his son's age now is x = 10
Rohan's age now = 6x - 30 +5
= ( 6 * 10 ) - 30 +5
= 60 - 30 + 5
= 30 + 5
= 35
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