Question

root 2 root 3 and root 18 are in AP find the 10th term

Answer 1

let AP be
2√3,√18,...
d=a2-a1
d=3√2-2√3
a10=a+(10-1)d
=2√3+9(3√2-2√3)
=2√3+27√2-18√3

a10=27√2-16√3