root of 6^n==1269 then what is n??
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Value of n is 8
Correcting the question:
To find n, given √(6ⁿ) = 1296
Step-by-step explanation:
Given,
√(6ⁿ) = 1296
or, (6ⁿ)^(1/2) = 1296
Squaring both sides, we get
(6ⁿ)^(2/2) = (1296)²
or, 6ⁿ = (6⁴)²
or, 6ⁿ = 6⁸
Comparing the like powers of 6 from both sides, we get
n = 8
However this problem can be solved with another approach:
Given,
√(6ⁿ) = 1296
or, (6ⁿ)^(1/2) = 6⁴
or, 6^(n/2) = 6⁴
Comparing the like powers of 6 from both sides, we get
n/2 = 4
or, n = 8
Laws of indices:
• √a = a^(1/2)
• (aᵇ)ᶜ = aᵇᶜ
• If aᵇ = aᶜ, then b = c
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