Question

root3= sinI/sin(90-I) solve

Answer 1

√3=sinl/sin(90-l)

$\sqrt{3} = \frac{sinl}{sin(90 - l)}$

$\sqrt{3} = \frac{sinl}{cosl}$

$\sqrt{3 } = tanl$

but,

tan60°=√3

so,

l=60°

hope it helps

:-)

Answer 2

Answer:

Pretty Easy Question

Step-by-step explanation:

No need for Detailed explanation