Question

roots of x^2-x-12=0​

Answer 1

Hope it is helpful.........

Answer 2

Step-by-step explanation:

${x }^{2} - x - 12 = 0$

${x}^{2} - (4 - 3)x - 12 = 0$

${x}^{2} - 4x + 3x - 12 = 0$

$x(x - 4) + 3(x - 4) = 0$

$(x - 4)(x + 3) = 0$

$(x - 4) = 0$

$x = 4$

$x + 3 = 0$

$x = - 3$

so,

$x = 4 \: or \: - 3$