Running at an average speed of 40 km per hour a bus complete a journey in 4 whole 1 by half hours how much time will the return journey take if the speed is increased to 45 km per hour with solution in inverse variation
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-5/8secs will inverse variation
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Speed of the bus=distance /time
Distance =speedxtime
=40x(4+1/2)
=40(5/2)
=100km
Now speed is 45km/hr
So reqd time=distance /speed
=100/45
=20/9
=2 full hours and 2/9 hour
Distance =speedxtime
=40x(4+1/2)
=40(5/2)
=100km
Now speed is 45km/hr
So reqd time=distance /speed
=100/45
=20/9
=2 full hours and 2/9 hour
mathupto12:
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