Question

S.I. unit of Reynold’s number is
(a) [ML⁻¹ T⁻¹] (b) [ML⁻³ T⁻¹]
(c) [M⁰ L⁰ T⁰] (d) [M⁰ LT⁻³]

Answer 1

Answer:

option C is correct..

because Reynolds's number is a dimension less quantity..

hope this helps you...