Question

सोचो और बताओ-
1. कवि नवयुग की नई वीणा में क्या भरने को कह रहे हैं?
2. पक्षी क्या कर रहे हैं?
3. कवि ने किसे संबोधित किया है?
4. इस कविता के रचयिता कौन हैं?​

Answer 1

Explanation:

जरा यह बताने की कृपा करेंगे कि एक किस पाठ से प्रश्न है

Answer 2

Answer:

Answer ➪

Answer ➪Mass of body M = 0.5kg

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100J

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mgh

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒ 100 = mgh

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒ 100 = mgh h    = 100 / (0.5 × 10)

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒ 100 = mgh h    = 100 / (0.5 × 10) h    = 20m

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒ 100 = mgh h    = 100 / (0.5 × 10) h    = 20m

Answer ➪Mass of body M = 0.5kgPotential energy P.E = 100JForce of gravity on 1 kg is 10 N→ F = mg→ 10 = 1 × g⇒ g = 10m/s²change in Potential energy= mg( h1 - h2 )= mg( h - 0 )= mghHeight ⇒ 100 = mgh h    = 100 / (0.5 × 10) h    = 20m ∴ The height of the tower is 20 m