Physics, asked by mohammedhusain179, 4 months ago

same quantity of water and kerosene are taken in two identical beakers. from the bottom of the two beakers air bubbles are rising. as shown in the figure
1.what is the reason for growth in size of the air bubble in both beakers as it rise upwards?
2.what is the reason for the large size of the air bubbles in kerosene compared to that in water? ​​

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Answers

Answered by qwmbappe
0

A bubble rises because there is more pressure at the bottom than at the top.

  • P Bottom > P Surface. As a result, the bubble rises.

  • V is proportional to 1/P at constant temperature (Boyle's law)

  • Since the pressure falls as the bubble rises, its volume will grow as a result of the above law, increasing the bubble's size.

  • Kerosene is less dense than water. Kerosene typically has a density of 0.8 g/cm3, whereas water typically has a density of 1 g/cm3.

  • Additionally, because the density is determined by dividing the fluid's mass by volume, kerosene requires a larger volume in order to have the same mass as water.

  • According to the equation Pressure = mass/area, this increases the surface area of the kerosene and lowers its pressure.

  • Water exerts pressure that is directly proportionate to its depth; as water depth increases, pressure in a body of water rises linearly.

  • As a result, as the depth of the water increases, so does the pressure it exerts on a body.

  • The pressure imposed on the bubble diminishes as it climbs because the depth of the bubble decreases.

  • The net pressure is towards the outside, which causes the bubble to extend as it rises in the water because the water's downward pressure on the bubble is less than the upward pressure from the air inside it.

#SPJ3

Answered by sumajiju93
0

can you plese explain me

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