Sandeep deposited 25000 rupees in a bank which place 8 % interest compounded annually how much would he get back after 2 years
Answers
Answered by
31
Hi ,
Principal ( p ) = Rs 25000
Rate of interest ( r ) = 8%
Time ( T ) = 2 years
Number of times interest paid ( n ) = 2
Amount ( A ) = p ( 1 + r/100 )^n
A = 25000 [ 1 + 8/100 ]²
= ( 25000 × 108 × 108 )/( 100 × 100)
= ( 25 × 108 × 108 )/ 10
= Rs 29160
Interest = A - P
= 29160 - 25000
= Rs 4160
I hope this helps you.
:)
Principal ( p ) = Rs 25000
Rate of interest ( r ) = 8%
Time ( T ) = 2 years
Number of times interest paid ( n ) = 2
Amount ( A ) = p ( 1 + r/100 )^n
A = 25000 [ 1 + 8/100 ]²
= ( 25000 × 108 × 108 )/( 100 × 100)
= ( 25 × 108 × 108 )/ 10
= Rs 29160
Interest = A - P
= 29160 - 25000
= Rs 4160
I hope this helps you.
:)
Answered by
0
Answer:
Amount He gets back = Rs. 29160
Step-by-step explanation:
Price = p = Rs. 25000
Rate of interest = r = 8% compounded annually
Time = n = 2 years
Amount = p (1 + %r / 100) ^ n
Amount = 25000 (1 + 8/100)^2
Amount = 25000 (100/100 + 8/100)^2
Amount = 25000 (108/100)^2
Amount = 25000 (1.08)^2
Amount = 25000 (1.1664)
Amount = Rs. 29160/-
At the end of 2nd year, The amount he receives is Rs. 29160/-
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