Question

Sanjay gets fixed monthly income . Every year there is a certain increment in his salary . After 4 year his monthly salary was 4500 and after 10 year his monthly salary become 5400 rupees .find his original salary and yearly increment .​

Answer 1

Let A be its first year salary D be the increament per year.

A.T.Q

T4= 4500 & T10 =5400

A + 3D = 4500

A + 9D = 5400

substracting

6D = 900

D = 150

A = 4500- 450= 4050 ( for one year)

one year --------->4050

12 months -----------> 4050

1 month -------------> 4050/12= 2025/6

one month salary = 2025/6

increament = 150

Answer 2

Answer:

Given that :

• Sanjay gets fixed monthly income.

• After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees

To find :

• His original salary and yearly increment.

Solution :

Let the original salary be 'x' .

Let his yearly increment be 'y'

After 4 years, his salary was Rs. 4500

⇒ x + 4y = 4500

⇒ x = 4500 - 4y ....... equation[1]

After 10 years, his salary becomes 54,00.

$\bold{Therefore,}$

⇒ x + 10y = 5400

⇒ 4500 - 4y + 10y = 5400

⇒ 6y = 900.

Putting the values in eq.[1],

⇒ x = 4500 - 4(150)

⇒ x = 4500 - 600 = 3900

$\bold{Hence,}$

His original salary was Rs. 3900 and increment per year was 150 Rs.