sanya's mom baked 47 cookies. Anil's dad baked 38 cookies. Sanya and anil ate 6 cookies each then brought them to school for a party. How many cookies did they bring to school altogether?
Answers
Answered by
2
HEY DEAR....
HERE'S YOUR ANSWER⬇
We know that :
# Total no. of cookies = 47+38= 85 cookies.
# Total no. of cookies
eaten by Sanya and Anil } = 6+6=12 cookies.
# No. of cookies bought to
school by them } = 85-12=73 Cookies.
Hence, together they bought 73 cookies to school for the party.
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
HERE'S YOUR ANSWER⬇
We know that :
# Total no. of cookies = 47+38= 85 cookies.
# Total no. of cookies
eaten by Sanya and Anil } = 6+6=12 cookies.
# No. of cookies bought to
school by them } = 85-12=73 Cookies.
Hence, together they bought 73 cookies to school for the party.
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
deepak676:
thank dear
Wlcm my dear. My happiness lies in helping you all ^_^
Answered by
2
Cookies baked by Sanya's mom = 47
Cookies baked by Anil's dad = 38
Total cookies baked = 47 + 38
= 85
Cookies ate by Sanya = 6
Cookies ate by Anil = 6
Total cookies ate = 12
Now,
Total cookies left = 85-12
= 73
I hope it's right
Cookies baked by Anil's dad = 38
Total cookies baked = 47 + 38
= 85
Cookies ate by Sanya = 6
Cookies ate by Anil = 6
Total cookies ate = 12
Now,
Total cookies left = 85-12
= 73
I hope it's right
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