Math, asked by anilchauhan735502, 8 months ago

Sarika's father is 25 years older than Sarika. After 10 years, he will be twice as old as Sarika. Fine theit present ages.​

Answers

Answered by piyushsharma82paxg79
10

Answer:

Let the sarika's age=x years

Then, father's AGE=x+25 years

After 10 years

sarika's age=x+10 years

father's age=x+25+100=x+35 years

According to the condition

2(x+10)=x+35

2x+20=x+35

2x-x=35-20

x=15

sarika's age=x=15 years

father's age=x+10=15+10=25 years

Step-by-step explanation:

Hope this helps you

Answered by sivasuryakumars
7

let sarika age = x

her father age = x +25

After 10 years,

sarika = x + 10

father = x + 25 + 10 = x + 35

According to the question,

2(x + 10) = x + 35

2x + 20 = x + 35

2x - x = - 20 + 35

x = 15

then, x + 25 = 15 + 25 = 40

Sarika age is 10.

her father age is 40.

MARK AS BRAINLESS

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