Question

sarita is twice as old as anushka.if six years is subtracted from Anushka age aand four years added to sarita age then Sarita will be four times Anushka s age . how old were they two years ago​

Answer 1

Your answer is 8years and 18years reaspectively.

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ExplanaTion:-

Given:-

• Sarita is twice as old as Anushka.

• If Six years is subtracted from Anushka's age and four years added Sarita's age then Sarite will be four times Anushka's age.

To Find:-

• How old they were 2 years ago.

Solution:-

• Let the age of Anushka be x Years.

• So age of sarita will be 2x Years.

• Also, if six years subtracted from Anushka's age than her age = (x - 6) years.

• And, If four years added to Sarita's age then her age = (2x + 4) years.

Therefore Acc. To Que.:-

↦ 4 × Anushka's age = Sarita's age.

↦ 4 × [(x - 6) years] = (2x + 4) years.

↦ 4x years - 24 years = 2x years - 4 years.

↦ 4x years - 2x years = -4 years + 24 years.

↦ 2x years = 20 years.

↦ x = 20 years/2 years.

↦ x = 10.

So now Anushka's age 2 years age

= (x - 2) years.

= (10 - 2) years.

= 8 years.

Similarly Sarita's age 2 years ago,

= (2x - 2) years.

= [(2 × 10) - 2] years.

= (20 - 2) years.

= 18 years.

Therefore Anushka's and Sarita's ages two years ago = 8 years and 18 years respectively.

Answer 2

Correct Question:

sarita is twice as old as anushka.if six years is subtracted from Anushka age aand four years added to sarita age then Sarita will be four times Anushka s age . how old were they two years ago

To find :

How old they were two years ago ?

Solution :

As we know that , we have to find the age of two years ago .

So , Let us assume Sarita's age = 2x and Anushka's age = x .

$= > 4(x - 6)3 = 2x + 4 \\ = 4x - 24 = 2x + 4 \\ = > 4x - 2x = 4 + 24 \\ = > 2x = 28 \\ = > x = \frac{28}{2} = 14$

So , the Anushka's present age = 14 .

And

Sarita's present age = 2x =2×14= 28.

Hence ,

=The Age of Anushka's two years back = 14 -2 = 12

=Sarita's age two years back = 28 - 2= 28.

Thanks!