sec 70° Sin 20°- cos20 cosec70 = 2
Answers
Answered by
4
Answer:
Step-by-step explanation:
sec 70° sin 20° + cos 20° cosec 70°
= sec (90° - 20°) sin 20° + cos 20° cosec (90° - 20°)
= cosec20° sin20° + cos20° sec20° [∵Sec(90°-A)=CosecA & Cosec(90° - A) = SecA ]
=sin20∘sin20∘+cos20∘cos20∘. [∵Cosec A=(1/SinA) & SecA =(1/CosA) ]
= 1 + 1 = 2
Answered by
0
Answer:
sec70=cosec20=1/sin20
similarly cosec70=sec20=1/cos20
Note- your q is wrong it should have a plus sign between
so LHS= 1+1=2
Hope this helps and mark me brainliest!!
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