Question

secβ-tanβ=3, then β lies in which quadrant
(a)1 (b) 2 (c) 3 (d) 4​

Answer 1

Answer:

1

becaus sec b - tan b = 1/cos b -sin b /cosb

=1-sin b/cos b

=cos^2 b/2 + sin^2 b/2 - 2sinb/2cos b/2

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cos^2 b/2 - sin^ b/2

= (cos b/2 -sin b/2)^2

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(cos b/2 -sin b/2) (cos b/2 + sin b/2)

=1/cos b/2+ sin b /2=3

=1=3(cos b/2 + sin b/2)

ie in first quadrant