sec theta plus tan theta = p then find sin theta in terms of p
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sec θ = 1/cos θ
tan θ = sin θ/cos θ
so, 1/cos θ + sinθ /cosθ = p
1+sinθ /cosθ = p [LCM]
cosθ is √sin² θ-1
1+sin θ / √sin² θ-1 = p
tan θ = sin θ/cos θ
so, 1/cos θ + sinθ /cosθ = p
1+sinθ /cosθ = p [LCM]
cosθ is √sin² θ-1
1+sin θ / √sin² θ-1 = p
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