Math, asked by nanditagupta, 1 year ago

sec2-cot2(90-theta)=cos2(90-theta)cos2theta

Attachments:

abhi1196199: esko proved krna hai na
abhi1196199: ki solve krna hai
nanditagupta: solve
Anonymous: in the RHS , minus sign is missing i think
nanditagupta: no
nanditagupta: if it is then try with using minus sign
Anonymous: lhs simplifies to 1
nanditagupta: send me the pic of the solution

Answers

Answered by mysticd
3
Hi ,

I think there is an error in the problem.

Here I am using A instead of theta

we know that,

1) cot( 90 - A ) = tanA

2 ) cos ( 90 - A ) = sinA

3 ) sec² A - tan² A = 1

4 ) sin² A + cos² A = 1

Now ,

according to the problem given ,

LHS = sec² A - cot² ( 90 - A )

= sec² A - tan² A

= 1

= sin² A + cos² A

= cos² ( 90 - A ) + cos² A

= RHS

I hope this helps you.

:)

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