sec²A- tan²A=1 find secA+tanA if secA-tanA =5
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Given:
• sec²A - tan²A = 1
• secA - tanA = 5
To find :
• sec A + tan A
Solution :
• sec² A - tan² A = 1
=>( sec A + tan A )( sec A - tan A ) = 1
=> (sec A + tan A)(5)=1
=> sec A + tan A = 1/5
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