Math, asked by siddharthrohen, 8 months ago

sec2x+cosec2x = sec2x×cosec2x

Answers

Answered by Cycan

7

Step-by-step explanation:

sec2x+cosec2x=1/cosx +1/sinx =sinx+cosx/sinxcosx=1/sinxcosx ( sinx+cosx=1)

sec2x * cosecx = 1/cosx * 1/sinx = 1/sinxcosx

so LHS=RHS

HENCE PROOVED

Answered by Anonymous

11

Answer

plz. mark it brainliest

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