Question

(secA + tanA) (1-sinA)​

Answer 1

Step-by-step explanation:

(secA+tanA)(1-sinA)

=secA+tanA-secA×sinA-tanA×sinA

=(1/cosA)+tanA-tanA-(sin²A/cosA)

=(1/cosA)-(sin²A/cosA)

=(1-sin²A)/cosA

=cos²A/cosA

=cosA

HOPE YOU UNDERSTAND DEAR ND PLZZ MARK IT AS BRILLIANT ☺☺

Answer 2

Step-by-step explanation:

secA = 1/cosA

tanA = sinA/cosA

SecA + tanA = (1/cosA) +(sinA/cosA)

= (1+sinA)/(cosA)

(SecA + tanA)(1-sinA)

= (1+ sinA)(1-sinA)/(cosA)

= (1-sin^2A)/cosA = cos^2A/cosA = cosA