English, asked by prakharshweta109251, 9 months ago

SecA-tanA/SecA+tanA=1-2SecAtanA+2Tan^2A

Answers

Answered by Anonymous
5

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Answered by Anonymous
0

Answer:

Explanation:

Sec A - Tan A / Sec A + Tan A  ×  Sec A - Tan A / Sec A - Tan A

= (Sec A - Tan A)² / (Sec A + Tan A)(Sec A - Tan A)

= (Sec A - Tan A)² / Sec²A - Tan²A

= Sec²A + Tan²A - 2 (Sec A × Tan A)

= 1 + Tan²A + Tan²A - 2 (Sec A × Tan A)

= 1 - 2 (Sec A × Tan A) + 2 Tan²A

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