Math, asked by namanbahri2, 2 months ago

Section
14. Factorise 4a2 + b2 + 25c2 - 4ab – 10bc + 20ca.​

Answers

Answered by EishanKhandait
3

Answer:

(2a-b+5a) (2a-b+5a)

Step-by-step explanation:

4a2 + b2 + 25c2 - 4ab – 10bc + 20ca.

= (2a)^2-(b)^2+(5c)^2-2.2a.b-2.b.5c+2.2a.5c

=(2a-b+5a)^2

=(2a-b+5a) (2a-b+5a)

Mark me Brainliest

Similar questions