Section
14. Factorise 4a2 + b2 + 25c2 - 4ab – 10bc + 20ca.
Answers
Answered by
3
Answer:
(2a-b+5a) (2a-b+5a)
Step-by-step explanation:
4a2 + b2 + 25c2 - 4ab – 10bc + 20ca.
= (2a)^2-(b)^2+(5c)^2-2.2a.b-2.b.5c+2.2a.5c
=(2a-b+5a)^2
=(2a-b+5a) (2a-b+5a)
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