Question

SECTION - C
Questions 27 to 34 carry 3 marks each.
27. The runs scored in a cricket match by 11 players is as follows:
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15
Find the mean, mode and median of this data.​

Answer 1

Answer:

Write the numbers in asending order.

6,8,10,15,50,80,100,120

median-15+50/2_32.5

mean is also known as average

mean_6+8+10+10+15+15+15+50+80+100+120/11

429/11

mean_39

Answer 2

Step-by-step explanation:

arranging the given data in ascending order

6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120

FORMULA USED:

$mean \: = \frac{sum \: of \: all \:observtions }{total \: no. \: of \: observations}$

$mean = \frac{(6 + 8 + 10 + 10 + 15 + 15 + 15 + 50 + 80 + 100 + 120)}{11}$

mean = 429 / 11

• MEAN = 39

FORMULA USED:

$median = just \: the \: middle \: term \\ \: \: \: \: \: \: \: for \: odd \: no. \: of \: observations \\ median = \frac{ {(n + 1)}^{th} }{2} term \\ median = \frac{(11 + 1)}{2} \\ median = \frac{ {12}^{th} }{2} \\ median = {6}^{th} term$

• MEDIAN = 15

MODE

FORMULA: observation which occurs most frequently

• MODE = 15