Math, asked by afisalady5954, 1 year ago

Seeta devi has 9 in fifty-paise and twenty five-paise coins. She has twice as many twenty five-paise coins as she has fifty-paise coins.how many coins of each kind does she have?

Answers

Answered by sophusonu
11

Let 50 paise coins be x in number.

Therefore 25 paise coins are 2x in number.

Value of 50 paise coins is 50x and value of 25 paise coins is 25 x 2x = 50x.

Total value is 900 paise.

Therefore, 50x + 50x = 900.

100x = 900.

x = 9.

Therefore, no. of coins of 50 paise is 9 and no of coins of 25 paise is 18.

Total coins = 27.

Answered by sanrajsingh33pb783l
7
Let 50 paise coins be x in number.

Therefore 25 paise coins are 2x in number.

Value of 50 paise coins is 50x and value of 25 paise coins is 25 x 2x = 50x.

Total value is 900 paise.

Therefore, 50x + 50x = 900.

100x = 900.

x = 9.

Therefore, no. of coins of 50 paise is 9 and no of coins of 25 paise is 18.

Total coins = 27.

I feel so proud of myself having solved this Class 6 sum.

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