Separate 178 in two parts so that the first part is 8 less than twice the second part
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Answered by
4
let the two parts be x and y
than, x + y = 178. (1)
it is given that....
x = 2y-8
=> x -2y = -8. (2)
from eq. (1) &(2), we get
y = 62
now, put the value of y in eq. (2)
x = 2* 62- 8
= 116
than, x + y = 178. (1)
it is given that....
x = 2y-8
=> x -2y = -8. (2)
from eq. (1) &(2), we get
y = 62
now, put the value of y in eq. (2)
x = 2* 62- 8
= 116
Answered by
2
x and y are two no.
x+y=178 (eq 1)
x=2y-8
x-2y =-8(eq 2)
subtracting eq 1 from eq 2
x+y=178
x-2y=-8
- + +
3y=186
y=62
x=2*62-8
x=124-8=116
x+y=178 (eq 1)
x=2y-8
x-2y =-8(eq 2)
subtracting eq 1 from eq 2
x+y=178
x-2y=-8
- + +
3y=186
y=62
x=2*62-8
x=124-8=116
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