Seven blocks each of mass 1o kg are arranged one above the other as shown in the figure. What are the values of the contact forces exerted on the third block; by the fourth block and the second block respectively? (Take g = 10/m²)
(A) 40 N, 50 N
(B) 50 N, 40 N
(C) 40 N, 20 N
(D) 50 N, 30 N
Answers
Answered by
4
Answer:
Option (A) 40 N, 50 N
Explanation:
The figure is attached
Contact force exerted in the third block by the fourth block will be equal to the weight of the 7th, 6th, 5th and 4th block
= (1+1+1+1)g
= 4 × 10
= 40 N
Contact force exerted in the third block by the 2nd block will be equal to the weight of the 7th, 6th, 5th and 4th and 3rd block
= (1+1+1+1+1)g
= 5 × 10
= 50 N
Hope this is helpful.
Attachments:
Similar questions