Question

Seven times a given two digit number is equal to four times the number obtained by reversing the order of the digits and the difference of the digits is 3

Answer 1

Hi ,

Let the unit place digit = x

ten's place digit = x -3

original number = 10( x - 3 ) + x

= 11x - 30----( 1 )

reversing the digits we get a new number

= 10x + ( x - 3 )

= 11x - 3 ------ ( 2 )

according to the problem given,

7 × ( 1 ) = 4 × ( 2 )

7 ( 11x - 30 ) = 4 ( 11x - 3 )

77x - 210 = 44x - 12

77x - 44x = 210 - 12

33x = 198

x = 198/33

x = 18/3

x = 6

Therefore ,

original number = 11x - 30

= 11× 6 - 30

= 66 - 30

= 36

I hope this helps you.

:)

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.