SEVEN TIMES TWO DIGITE NUMBER IS EQUAL TO FOUR TIMES THE NUMBER OBTAINED BY REVERING THE ORDER OF ITS DIGITS IF DIFFERENCE OF THE DIGIT IS 3
Answers
Answer :
Let, the digits in ones place and tens place are x and y respectively.
Then, the number be A = ( 10y + x )
When the digits will be altered, x will be in tens place and y will be in ones place.
So, the number becomes B = ( 10x + y )
By the given conditions,
7A = 4B
⇒ 7 ( 10y + x ) = 4 ( 10x + y )
⇒ 70y + 7x = 40x + 4y
⇒ 40x - 7x = 70y - 4y
⇒ 33x = 66y
⇒ x = 2y .....(i)
Also given that, the difference between x and y is 3
⇒ x - y = 3
⇒ 2y - y = 3, by (i)
⇒ y = 3
Putting y = 3 in (i), we get
x = 2 * 3 = 6
So, the required number be 10 * 6 + 3 = 63
and the reversed number be 36.
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Answer:
36
Step-by-step explanation:
Let the unit digit be a and tenth unit be b .
So , number = 10 b + a
It's said number is seven times is equal to reversing the order of its digit.
= > 7 ( 10 b + a ) = 4 ( 10 a + b )
= > 70 b + 7 a = 40 a + 4 b
= > 66 b = 33 a
= > a = 2 b ... ( i )
Also given numbers' difference is 3 .
a - b = 3 ( ii )
From ( i ) and ( ii ) we get :
a b - b = 3
b = 3
= > a = 6
Hence number = > 30 + 6