Question

Shalini plants 4 sapling in a row in her .Gardens the distance between two adjacent saplings is 3/4.find the distance the first and last sapling

Answer 1

HEY DEAR ...

Total no. of saplings planted by Saili in a row = 4.

So let us say thet the four splings are A, B, C and D.

Since there are four saplings, so the gap between them will be three. As A-------B--------C---------D.

The gap between first and second sapling is 3/4 Mtrs.

So the distance between first and the last sapling will be 3/4 x 3 = 9/4 = 2 1/4 Mtrs.

Ans: 2 1/4 Mtrs.

HOPE , IT HELPS ...

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• The distance between the first and last saplings = $\sf {2 \dfrac{1}{4} \:m}$

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• Shalini plants 4 sapling in a row in her garden. The distance between two adjacent saplings is $\sf {\dfrac{3}{4} }$.

$\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}$

• The distance between the first and last saplings = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

Let the saplings be planted at positions A, B, C, and D as shown in the figure given below:

$\setlength{\unitlength}{20}\begin{picture}(5,2) \put(1,2){\line(1,0){6}} \put(1,2){\circle*{0.2}} \put(3,2){\circle*{0.2}}\put(5,2){\circle*{0.2}}\put(7,2){\circle*{0.2}}\put(0.85,1.5){ \tt A }\put(2.85,1.5){ \tt B } \put(4.85,1.5){ \tt C }\put(6.85,1.5){ \tt D }\end{picture}$

$\sf {The\: distance\: between\:two\: adjacent\: saplings = \dfrac{3}{4} \:m}$

$\sf\underline{\red{\:\:\: Note\:That:-\:\:\:}}$

• There are 3 gaps between first and last saplings.

$\sf\underline{\pink{\:\:\: A.T.Q:-\:\:\:}}$

$\dashrightarrow \sf {Distance\: between\: first\:and\:last\: saplings = \bigg(3 \times \dfrac{3}{4}\bigg)\:m }$

$\dashrightarrow \sf {Distance\: between\: first\:and\:last\: saplings = \dfrac{9}{4}\:m}$

$\dashrightarrow \sf {Distance\: between\: first\:and\:last\: saplings = 2 \dfrac{1}{4} \:m}$

$\sf\underline{\green{\:\:\: ThereFore:-\:\:\:}}$

• The distance between the first and last saplings is $\sf {2 \dfrac{1}{4} \:m}$

$\rule{250}{2}$