Shanti lal left one fifth of his property of his sons,one fifth for his daughter and the remainder for his wife , if wife's share in the property was worth 288000,find the totel worth of Shanti lal's property.
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Answered by
13
let the total property be X then
sons share =( 1/5)*X
daughters share = (1/5)*X
wifes share = 288000
now
sons share + daughters share + wife's share = total property
(1/5)*X + ( 1/5)*X + 288000= X
(2/5)*X + 288000= X
288000 = (3/5)*X
X = 91000*5 = 455000 rs
sons share =( 1/5)*X
daughters share = (1/5)*X
wifes share = 288000
now
sons share + daughters share + wife's share = total property
(1/5)*X + ( 1/5)*X + 288000= X
(2/5)*X + 288000= X
288000 = (3/5)*X
X = 91000*5 = 455000 rs
Answered by
0
Answer:
let total property of Shanti Lal be x
Step-by-step explanation:
son,s share = 1/5x
daughter,s share =1/5x
wIfe,s share = 288000
Then, son,s + daughter,s share +wife,s share = x
1/5x + 1/5x + 288000= x
2/5x - x = 288000
3/5x = 288000
x = 288000 / (3/5)
x = 480000
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