_____ should be subtractes from 3x³-1 to get x³
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Answered by
4
let y be subtracted from (3x^3-1)
therefore, it becomes,
(3x^3-1)-(y)=x^3
(3x^3-1)-x^3=y
so open the brackets,
3x^3-1-x^3=y
2x^3-1=y
2x^3=y+1
x^3=[(y+1)/2]
But i don't know its correct or not.
therefore, it becomes,
(3x^3-1)-(y)=x^3
(3x^3-1)-x^3=y
so open the brackets,
3x^3-1-x^3=y
2x^3-1=y
2x^3=y+1
x^3=[(y+1)/2]
But i don't know its correct or not.
Answered by
8
let we have to subtract A then
(3x^3-1)-A=x^3
(3x^3-1)=x^3+A
(3x^3-1)-x^3=A
(3x^3-x^3)-1=A
2x^3-1=A
so ans is 2x^3-1
(3x^3-1)-A=x^3
(3x^3-1)=x^3+A
(3x^3-1)-x^3=A
(3x^3-x^3)-1=A
2x^3-1=A
so ans is 2x^3-1
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