show that 0.3 bar can be expressed in the form p/q , whose p and q are integers q is not 0
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1
Let x=0.3bar ---eq1
Multiplying eq 1 by 10
That is
10x=3.3bar
Now subtract eq 1 from eq 2
10x-x=3.3bar-0.3bar{.3bar will be cancelled by each other}
Now
9x=3
X=3/9
X=1/3
Multiplying eq 1 by 10
That is
10x=3.3bar
Now subtract eq 1 from eq 2
10x-x=3.3bar-0.3bar{.3bar will be cancelled by each other}
Now
9x=3
X=3/9
X=1/3
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27
Answer:
Given: 0.3 bar.
So, let us assume variable (a) as 0.3 bar.
⇢a = 0.3333...
⇢10a = 10 × (0.333...) = 3.333...
⇢3.333... = 3 + a
⇢a = 0.333...
⇢10a = 3 + a
⇢9a = 3
⇢a = 1/3
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