Show that √2-3√(5) irrational
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mohdzayeem2:
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hola frnd!!!!!
hr u go....
dr r 2 solutions...
SOLUTION 1:
assume 2-3√5 be a rational number
therefore, 2-3√5 = a/b
hence, √5 = a-2b/3b
therefore, a-2b/3b is a rational number
therefore, √5 is a rational number
but we know that √5 is an irrational number
therefore, our assumption was wrong that 2-3√5 is a rational number
therefore, 2-3√5 is an irrational number
SOLUTION 2:
let 2-3√5 be rational number
and 2 is also a rational number
so, 2-3√5-2 is also a rational number
therefore, 3√5 is a rational number
and 3 is also rational number
so, 3√5/3 is also a rational number
therefore, √5 is a rational number
but √5 is an irrational number
therefore, it is a contradiction
so, 2-3√5 is an irrational number
hope dat 8list any1 solution wud hlp u.....
#be brainly ^_^
Regards,
SAMEERA❤️
hr u go....
dr r 2 solutions...
SOLUTION 1:
assume 2-3√5 be a rational number
therefore, 2-3√5 = a/b
hence, √5 = a-2b/3b
therefore, a-2b/3b is a rational number
therefore, √5 is a rational number
but we know that √5 is an irrational number
therefore, our assumption was wrong that 2-3√5 is a rational number
therefore, 2-3√5 is an irrational number
SOLUTION 2:
let 2-3√5 be rational number
and 2 is also a rational number
so, 2-3√5-2 is also a rational number
therefore, 3√5 is a rational number
and 3 is also rational number
so, 3√5/3 is also a rational number
therefore, √5 is a rational number
but √5 is an irrational number
therefore, it is a contradiction
so, 2-3√5 is an irrational number
hope dat 8list any1 solution wud hlp u.....
#be brainly ^_^
Regards,
SAMEERA❤️
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