Question

Show that 2^n cannot end with digit 5 for any natural number n​

Answer 1

Answer:

If n is a natural number

Then 2^n is a multiple of 2

Hence last digit must be even 2,4,6,8

Hence 2^n cannot end with digit 5

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Answer 2

Answer:

2²n cannot be odd and cannot end with 5 because square or any other power can be only an even end number.

double of the number will be always an even

5 can only be exist in powers of 5 power n