Show that (3x-2) is a factor of (3x+x-20x+12x)
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Answered by
0
If 3x - 2 is a factor, then 3x - 2 = 0 ⇒ x = 2/3 should satisfy the equation
3x² - 20x+12 = 3(4/9) - 40/3 + 12 = 0
So, it is a factor of 3x² - 20x+12
3x² - 20x+12 = 3(4/9) - 40/3 + 12 = 0
So, it is a factor of 3x² - 20x+12
Answered by
14
Hello Dear!!!
Here's your answer...
f(x) = (3x+x-20x+12x)
g(x) = 3x-2
zero of g(x) =
3x-2 = 0
3x=2
x= 2/3
substitute the value of x in f(x)
(3x+x-20x+12x)
( 3*2/3 + 2/3 - 20*2/3 + 12*2/3)
(2 + 2/3 - 40/3 + 4*2)
(2 + 2/3 - 40/3 + 8)
LCM is 3
(6/3 + 2/3 - 40/3 + 24/3)
(-8/3)
Its not a factor of (3x+x-20x+12x)
But if ur question is (3x^2-20x+12)
then
substitute value of x
(3×4/9 - 20*2/3 + 12)
(4/3 - 40/3 + 36/3)
(0/3)
0.
so...it is a factor...
I think so ur question is wrong because I have tried for question... but it is not a factor...
and then I took the form of ax^2+bx+c...then its correct...
post your question properly from next time...
__________________________________
hope this helps you....
Here's your answer...
f(x) = (3x+x-20x+12x)
g(x) = 3x-2
zero of g(x) =
3x-2 = 0
3x=2
x= 2/3
substitute the value of x in f(x)
(3x+x-20x+12x)
( 3*2/3 + 2/3 - 20*2/3 + 12*2/3)
(2 + 2/3 - 40/3 + 4*2)
(2 + 2/3 - 40/3 + 8)
LCM is 3
(6/3 + 2/3 - 40/3 + 24/3)
(-8/3)
Its not a factor of (3x+x-20x+12x)
But if ur question is (3x^2-20x+12)
then
substitute value of x
(3×4/9 - 20*2/3 + 12)
(4/3 - 40/3 + 36/3)
(0/3)
0.
so...it is a factor...
I think so ur question is wrong because I have tried for question... but it is not a factor...
and then I took the form of ax^2+bx+c...then its correct...
post your question properly from next time...
__________________________________
hope this helps you....
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