Math, asked by yagya123, 1 year ago

Show that (3x-7)^2-84x=(3x-7)^2

Answers

Answered by Anonymous

66

3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

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Answered by 1Lakshika

76

3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

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